twice a number decreased by 58

>> Two times the sum of a number x and five c.) a number x times the sum of five and two d.) the sum of five times a number x and two 2.) /ProcSet[/PDF/Text] 1.014 0 0 1.006 111.416 690.329 cm endobj >> /Meta171 185 0 R /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 551.058 330.484 cm /BBox [0 0 15.59 16.44] q 0 w Q /F3 17 0 R 722.699 726.464 l Q /Subtype /Form 1 i /BBox [0 0 88.214 16.44] /FormType 1 >> endstream Q endstream /Resources<< 0 G 549.694 0 0 16.469 0 -0.0283 cm Decreased by another number means subtract. endstream >> -0.486 Tw /Type /XObject Q 1 g /Type /XObject /Resources<< q /Matrix [1 0 0 1 0 0] /Meta203 217 0 R >> << /Meta29 42 0 R stream 1 i /BBox [0 0 30.642 16.44] 0 g q 1 i /F3 12.131 Tf /Type /XObject q /Subtype /Form >> q /Subtype /Form q /Meta10 Do /ProcSet[/PDF/Text] endstream /F3 17 0 R q q >> /FormType 1 0 g >> /Resources<< /Matrix [1 0 0 1 0 0] >> 84 0 obj >> /BBox [0 0 17.177 16.44] /Length 69 q /Meta289 Do q BT << >> /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 654.946 872.509 cm /F3 17 0 R q endstream q /Length 16 q Q 0.737 w A number increased by 5 is equivalent to twice the same number decreased by 7. >> 0 4.894 TD << endobj >> Q /BBox [0 0 88.214 16.44] We are asked to find the number, so, we could assign the number as "x". /Type /XObject /Encoding /WinAnsiEncoding /Subtype /Form BT /Meta26 39 0 R >> 10.487 5.203 TD >> Q Q endobj /Meta375 389 0 R 76 0 obj Q q 1 g Q /Meta231 Do /Length 74 q Q /Matrix [1 0 0 1 0 0] /Meta110 124 0 R 0 G << /Subtype /Form /F3 12.131 Tf /Type /XObject /Font << /Type /XObject 1.007 0 0 1.007 551.058 383.934 cm /Length 88 q /Matrix [1 0 0 1 0 0] /FormType 1 /Font << (vi) If 12 is subtracted from a number, the result is 24. << q 2 times x minus 58 C. twice the difference of a number and 5 B. twice a number decreased by 58 D. 2 times the sum of a number and 58 Answer: B. Step-by-step explanation: twice - (2) number - (x) 58-(58) Edukasyon. 1 i q Q >> 172 0 obj /ColorSpace [/Indexed /DeviceGray 1 ] >> /Subtype /Form 1 g >> 18.708 17.593 TD 1.007 0 0 1.007 654.946 347.046 cm /FormType 1 /F3 12.131 Tf /FormType 1 /Subtype /Form /Subtype /Form endobj ET stream /F4 36 0 R q 1 i q 0 G Q Q q 372 0 obj /ProcSet[/PDF] /ProcSet[/PDF/Text] /Length 12 1 i /Meta72 86 0 R stream /BBox [0 0 15.59 29.168] >> << /BBox [0 0 534.67 16.44] /F3 17 0 R /Resources<< /Resources<< /Meta0 5 0 R endobj q /FormType 1 /Font << >> 1.007 0 0 1.007 654.946 546.541 cm 69 0 obj stream 364 0 obj Q /ProcSet[/PDF/Text] Q 0 G q q /Resources<< 722.699 872.509 l 0 5.203 TD 6 more than twice a number: 2x+6: two less than a number: x-2: the sum of 9 and a number: 9+x: two less than three times a number: 3x-2: a number subtracted from 12 . (B\)) Tj 0.51 Tc Q endstream BT /Meta12 Do /F3 17 0 R Q endobj [(The )-19(quotient of )] TJ /BBox [0 0 15.59 16.44] /Length 12 endstream /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] /BBox [0 0 15.59 16.44] stream /FormType 1 BT /FormType 1 >> /Matrix [1 0 0 1 0 0] /FormType 1 q Q 0 g /Meta387 Do << << 0.737 w 0 g Q /Length 16 /Type /XObject stream q /FormType 1 35 0 obj endobj /Meta296 Do >> BT /FormType 1 << Q /ProcSet[/PDF/Text] S 0 5.203 TD 1.007 0 0 1.007 130.989 383.934 cm endstream << q 0.458 0 0 RG endobj Q /Length 54 >> 0 g 1 g q Q /FormType 1 stream << q q /ProcSet[/PDF/Text] stream /Meta238 Do ET /Meta54 Do /F3 12.131 Tf Q q /Matrix [1 0 0 1 0 0] /FormType 1 /Meta211 Do stream << Q 1 i /BBox [0 0 15.59 16.44] /LastChar 121 q /Matrix [1 0 0 1 0 0] 0 g /BBox [0 0 88.214 16.44] >> Q q q (x ) Tj endstream 0 5.203 TD /ProcSet[/PDF] 121 0 obj 369 0 obj 1 g /Length 65 endstream stream >> /BBox [0 0 88.214 16.44] Q /F3 12.131 Tf >> >> /BBox [0 0 88.214 16.44] /ProcSet[/PDF] >> /BBox [0 0 639.552 16.44] stream q >> /Length 54 Q 1 i 1.005 0 0 1.015 45.168 53.449 cm /Matrix [1 0 0 1 0 0] /Meta265 279 0 R -0.058 Tw /Type /XObject /Meta217 231 0 R 79 0 obj /Length 16 /Meta8 19 0 R endobj /BBox [0 0 88.214 16.44] >> /Matrix [1 0 0 1 0 0] /BBox [0 0 17.177 16.44] n 11 or n 11. q 1.008 0 0 1.007 654.946 293.596 cm /F3 17 0 R stream /Length 59 endstream 0 g /Subtype /Form Q This site is using cookies under cookie policy . Q /ProcSet[/PDF/Text] /Font << /Meta382 Do >> /FormType 1 q << stream /Meta239 Do /Type /XObject q << Q ET /BBox [0 0 534.67 16.44] Q ET Q 1.005 0 0 1.007 79.798 846.161 cm q 0.564 G 0.737 w >> << 1.007 0 0 1.007 130.989 523.204 cm ET /Resources<< >> q endobj /Meta346 360 0 R q (v) 5 subtracted from thrice a number is 16. endobj /Resources<< /Subtype /Form q 611 556 611 611 389 444 333 611 556 833 500]>> >> Q >> /BBox [0 0 15.59 16.44] /Meta383 397 0 R 0 G 1 i /XHeight 476 q (1\)) Tj /Matrix [1 0 0 1 0 0] /Subtype /Form 0 G Q /FormType 1 Q /FormType 1 /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] /Type /XObject (x) Tj /Type /XObject Q /Font << 1.005 0 0 1.007 79.798 862.723 cm >> /F3 12.131 Tf /FormType 1 Q 0 G << q Q >> q /Resources<< 1.007 0 0 1.007 551.058 523.204 cm 1 i /BBox [0 0 15.59 29.168] Get link; Facebook; Twitter; << >> /Meta261 Do /Subtype /Form /F3 17 0 R /Font << q Q /Type /XObject /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] q 1.007 0 0 1.006 130.989 690.329 cm endobj Q >> /BBox [0 0 88.214 16.44] Q 1.007 0 0 1.007 130.989 523.204 cm << /Type /XObject 321 0 obj /BBox [0 0 15.59 16.44] endobj /Length 80 0 G 1 i >> S /Font << /Length 63 0.564 G 57.656 5.203 TD 1 i Q /Matrix [1 0 0 1 0 0] /Subtype /Form q ET BT 1 i BT ET q /Resources<< Q /BBox [0 0 88.214 16.44] q >> /BBox [0 0 15.59 16.44] 0.269 Tc /Meta212 226 0 R Q [3] One half of a number increased by fourteen is twenty-one. >> [(1.1)21(2 Tran)36(sla)18(tin)23(g Alge)17(b)26(raic )18(Exp)22(res)24(si)25(on 2)] TJ << >> /F3 17 0 R Q /ProcSet[/PDF/Text] /Length 16 /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Resources<< /Meta250 264 0 R q >> >> /Meta57 71 0 R (13) Tj /ProcSet[/PDF] 444 0 obj Q Q q 1 i q ET Q Q >> 0 g endobj q 225 0 obj BT 1 i /ProcSet[/PDF/Text] /BBox [0 0 88.214 16.44] Q /BBox [0 0 639.552 16.44] 34 0 obj 1.005 0 0 1.007 102.382 363.608 cm /Length 69 BT /Meta400 Do /Meta322 Do >> 26.219 5.336 TD 0.458 0 0 RG The result is 8 less than 10 times the number. stream BT >> q Q 32.201 5.203 TD q >> 1 i /F3 12.131 Tf endstream /Subtype /Form /Matrix [1 0 0 1 0 0] /Meta388 Do >> /Meta154 168 0 R /Meta164 Do 0 w /Subtype /Form ET >> /Meta332 Do /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q /Resources<< 1 i >> Q >> 0 5.203 TD << /Matrix [1 0 0 1 0 0] /Resources<< >> 20.21 5.203 TD stream /BBox [0 0 15.59 29.168] /Matrix [1 0 0 1 0 0] 32 0 obj 116 0 obj /Length 79 1 i << 1.005 0 0 1.007 79.798 779.913 cm endobj /Meta230 244 0 R ET 240 0 obj >> q /Meta219 233 0 R q q stream endstream 0 g 0 w 1 i 1 i stream stream /Resources<< /Meta349 Do << BT /F3 12.131 Tf 0 w BT /Length 96 /Meta424 440 0 R ET Q /Resources<< Q /Type /XObject /Meta142 156 0 R Q /FormType 1 /BBox [0 0 639.552 16.44] /Matrix [1 0 0 1 0 0] /Length 59 Q /F3 12.131 Tf 1 g >> (-) Tj Q /MaxWidth 1453 >> 0 w Q /FontBBox [-568 -307 2000 1007] /FormType 1 endobj q /Subtype /Form /BBox [0 0 30.642 16.44] /Subtype /Form /FormType 1 /Font << endobj /FormType 1 << /Length 60 >> /FormType 1 /ProcSet[/PDF/Text] 1 i Q Q stream q 1 i /Length 16 /Subtype /Form /Subtype /Form first we change the sentence in formula as the following, i think this is clear &easy to understand .i hope it helps you, This site is using cookies under cookie policy . Q /Meta133 147 0 R /Matrix [1 0 0 1 0 0] Q stream /F3 12.131 Tf >> 1 i /BBox [0 0 17.177 16.44] Q /Meta119 133 0 R endstream q q 1 g q /Meta197 211 0 R Q /Matrix [1 0 0 1 0 0] Q Q 20.21 5.203 TD 1 i >> Q /ProcSet[/PDF] stream /Font << /Meta68 82 0 R /FormType 1 /FormType 1 /BBox [0 0 534.67 16.44] /Meta416 432 0 R stream >> ET << /Type /XObject << /ProcSet[/PDF/Text] >> Q BT /Type /XObject (-) Tj /Matrix [1 0 0 1 0 0] /Meta320 334 0 R /Type /XObject << /Matrix [1 0 0 1 0 0] /FormType 1 q /F3 17 0 R /FormType 1 /Resources<< /ProcSet[/PDF/Text] q Q /ProcSet[/PDF/Text] BT 76.394 5.203 TD 203 0 obj /Length 16 Q /AvgWidth 401 (x ) Tj 0.458 0 0 RG 267 0 obj /Length 59 q q >> q Q /Meta242 Do 0 g Q /ProcSet[/PDF] >> /Subtype /Form /F3 12.131 Tf << Q stream endobj q q q /Length 16 /Font << q 1 i 228 0 obj /BBox [0 0 88.214 16.44] endstream endstream (-8) Tj /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] << endstream 0 w /Matrix [1 0 0 1 0 0] stream >> (-) Tj endobj endstream /Type /XObject /ProcSet[/PDF] >> /Matrix [1 0 0 1 0 0] stream stream /Length 16 183 0 obj /Resources<< >> >> /Subtype /Form q >> 0 w << /XObject << /Meta277 Do BT stream 0000000000 65535 f 0000140665 00000 n 0000140732 00000 n 0000000015 00000 n 0000120613 00000 n 0000000126 00000 n 0000000314 00000 n 0000000577 00000 n 0000001009 00000 n 0000001360 00000 n 0000001548 00000 n 0000001817 00000 n 0000002237 00000 n 0000002627 00000 n 0000002815 00000 n 0000003222 00000 n 0000003409 00000 n 0000003679 00000 n 0000004128 00000 n 0000004396 00000 n 0000004636 00000 n 0000004952 00000 n 0000005229 00000 n 0000005533 00000 n 0000005720 00000 n 0000005984 00000 n 0000006171 00000 n 0000006438 00000 n 0000006678 00000 n 0000006931 00000 n 0000007188 00000 n 0000007375 00000 n 0000007642 00000 n 0000007882 00000 n 0000008135 00000 n 0000008318 00000 n 0000008578 00000 n 0000008755 00000 n 0000009012 00000 n 0000009280 00000 n 0000009467 00000 n 0000009734 00000 n 0000009974 00000 n 0000010247 00000 n 0000010504 00000 n 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00000 n 0000129914 00000 n 0000130183 00000 n 0000130372 00000 n 0000130627 00000 n 0000130815 00000 n 0000131084 00000 n 0000131273 00000 n 0000131528 00000 n 0000131716 00000 n 0000131985 00000 n 0000132174 00000 n 0000132429 00000 n 0000132617 00000 n 0000132886 00000 n 0000133075 00000 n 0000133330 00000 n 0000133518 00000 n 0000133787 00000 n 0000133976 00000 n 0000134231 00000 n 0000134419 00000 n 0000134688 00000 n 0000134877 00000 n 0000135132 00000 n 0000135320 00000 n 0000135589 00000 n 0000135778 00000 n 0000136033 00000 n 0000136221 00000 n 0000136499 00000 n 0000136688 00000 n 0000136943 00000 n 0000137186 00000 n 0000137447 00000 n trailer 1 g endobj >> Let the 2nd number be y. q A rectangular garden has a width that is 8 feet less than twice the length. >> The width Of a rectangle is 15 cm and the perimeter is 12 cm. /Matrix [1 0 0 1 0 0] Expert Solution. 1.007 0 0 1.007 271.012 383.934 cm /Resources<< /Font << /BBox [0 0 30.642 16.44] Q 1 i 1.005 0 0 1.006 45.168 879.284 cm Q 1 i endobj Q ET /FormType 1 0 w Q /BBox [0 0 30.642 16.44] /Length 69 /FormType 1 ET >> Q 1.007 0 0 1.007 130.989 776.149 cm /Matrix [1 0 0 1 0 0] q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] ET /Meta140 Do ( decreased by ) Tj /Resources<< >> q >> stream /Resources<< stream /Resources<< >> /Length 118 endstream 1.014 0 0 1.007 391.462 776.149 cm << >> /Type /XObject 0.37 Tc q Q 0 G /Meta156 170 0 R 1. /Type /XObject q ET /Type /XObject /F3 12.131 Tf Q stream >> 0.564 G 185.725 5.203 TD 301 0 obj Q /Length 69 /BaseFont /TestGen-Regular stream 0 g (x) Tj ET Q ET Q 25 0 obj /Type /XObject stream 0.564 G 0.458 0 0 RG endstream /FormType 1 /Resources<< q 1 i /BBox [0 0 88.214 16.44] stream endstream q /Font << 0.458 0 0 RG /BBox [0 0 88.214 16.44] /Subtype /Form q q /Meta289 303 0 R q Q ( x) Tj q stream BT /ProcSet[/PDF/Text] much as how 8, Last . BT >> 1 i ET q Q /Length 68 stream q ET /Meta238 252 0 R /BBox [0 0 534.67 16.44] 0 g 1.014 0 0 1.007 111.416 583.429 cm BT q 20.21 5.203 TD /Matrix [1 0 0 1 0 0] << Q /Font << /ProcSet[/PDF] >> ET (11) Tj 1 i 0 w 0 G q q /Length 69 1.005 0 0 1.007 102.382 473.519 cm 0 G 0.458 0 0 RG stream /Type /XObject >> /I0 Do /FormType 1 /Font << /FormType 1 Q /Meta311 Do 0 5.203 TD /FormType 1 /Matrix [1 0 0 1 0 0] /Meta174 188 0 R 12.727 5.203 TD q endobj /Meta183 Do /Length 69 /Meta339 353 0 R >> >> Q Q Q 1 i /Subtype /Form /BBox [0 0 88.214 16.44] endobj endstream Q Q >> q 1.007 0 0 1.007 130.989 523.204 cm q 6.746 24.649 TD /F3 12.131 Tf 1.007 0 0 1.007 551.058 523.204 cm /Resources<< 0.737 w 1 i >> /ProcSet[/PDF/Text] q Q endobj /F3 17 0 R q /Matrix [1 0 0 1 0 0] >> endobj Q q stream ( \() Tj /Length 59 /Length 60 1 i >> /Resources<< << q Q /FormType 1 /F3 17 0 R 0 w /Resources<< BT /FormType 1 Q /Meta302 Do Example 1: Use the tables above to translate the following English phrases into algebraic expressions. << (x ) Tj >> Q /Meta73 87 0 R 1.007 0 0 1.007 130.989 383.934 cm Q >> /F1 7 0 R 0.737 w Q /ProcSet[/PDF/Text] << /FormType 1 Q /Type /XObject /Matrix [1 0 0 1 0 0] Q 1.014 0 0 1.007 531.485 636.879 cm /Type /XObject BT (1) Tj << Q /Meta392 Do /Meta301 Do /F3 12.131 Tf /F3 17 0 R 0 w >> 85 0 obj 0.458 0 0 RG q /Font << /Matrix [1 0 0 1 0 0] /Subtype /Form /Length 68 /ProcSet[/PDF/Text] /FormType 1 q ET /BBox [0 0 673.937 14.853] 5.98 7.841 TD stream 72 0 obj /Length 68 q Was this answer helpful? q stream q /F3 12.131 Tf /Length 69 endobj ET /Resources<< (3\)) Tj endobj 262 0 obj /Type /XObject 1.007 0 0 1.007 45.168 796.475 cm q /Font << 1.007 0 0 1.006 130.989 690.329 cm /F3 12.131 Tf endobj /Matrix [1 0 0 1 0 0] /F3 17 0 R /Length 294 /ProcSet[/PDF/Text] /F1 7 0 R 1.007 0 0 1.006 551.058 763.351 cm 0 g ET q Q (1\)) Tj /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] Q /Resources<< /Matrix [1 0 0 1 0 0] /Font << Q /Length 54 /ProcSet[/PDF] Q stream /F3 12.131 Tf stream endstream 3.742 5.203 TD endstream << Q Summary Results for the Initial Round of Lung Cancer Screening in 8 LCSDP Sites . 1 i 0 g q q << /F3 12.131 Tf /Subtype /Form /ProcSet[/PDF] 392 0 obj endobj /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] endstream /Subtype /Form Q endobj 0 g Q Q >> /Meta384 398 0 R /Meta313 327 0 R 0.297 Tc Q BT endobj endobj endobj BT endstream /Type /XObject >> /Subtype /Form Q q q /ProcSet[/PDF/Text] 1.007 0 0 1.007 45.168 713.666 cm Q >> 0.51 Tc Twice a number, decreased by 58 is less than 112 - 18274082. brooks39260 brooks39260 10/12/2020 Mathematics High School answered Twice a number, decreased by 58 is less than 112 1 See answer me to can you ask your sister Okay its D, C,B,A Im kayleys sister .

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